x^2-15x=23

Solution for x^2-15x=23 equation:

x^2-15x=23

We move all terms to the left:

x^2-15x-(23)=0

a = 1; b = -15; c = -23;
Δ = b2-4ac
Δ = -152-4·1·(-23)
Δ = 317
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-\sqrt{317}}{2*1}=\frac{15-\sqrt{317}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+\sqrt{317}}{2*1}=\frac{15+\sqrt{317}}{2}
$